<PRE><B>Question 985133</B>
.
D=original number of dogs; C= original number of cats
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D=C+10 Ten more dogs than cats
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D-2=2(C+2) Substitute for C
(C+10)-2=2(C+2)
C+8=2C+4
4=C The shop originally had 4 cats.
The shop bought two cats so: 
4+2=6 
ANSWER: The shop now has 6 cats.
.
Original number of dogs:
D=C+10=4+10=14 The shop originally had 14 dogs.
The shop sold two dogs:
14-2=12 The shop now has 12 dogs.
12 dogs is twice as many as 6 cats.</PRE>