Question 985100

same as Question 985109

{{{x+y+z=1}}}.......eq.1
{{{3x-2y-z=5}}}.......eq.2
{{{x+3y+2z=3}}} .......eq.3
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{{{x+y+z=1}}}.......eq.1
{{{3x-2y-z=5}}}.......eq.2
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{{{x+y+cross(z)+3x-2y-cross(z)=1+5}}}

{{{x+y+3x-2y=6}}}
{{{4x-y=6}}}...............solve for {{{y}}}

{{{y=4x-6}}}.........eq.1a


{{{x+y+z=1}}}.......eq.1....multiply by {{{2}}}
{{{x+3y+2z=3}}} .......eq.3
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{{{2x+2y+2z=2}}}.......eq.1 
{{{x+3y+2z=3}}} .......eq.3
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{{{2x+2y+cross(2z)-x-3y-cross(2z)=2-3}}}.

{{{2x+2y-x-3y=-1}}}

{{{x-y=-1}}}........solve for {{{y}}}

{{{y=x+1}}}..............eq.2a

from eq.1a and eq.2a we have

{{{4x-6=x+1}}}......solve for {{{x}}}

{{{4x-x=6+1}}}
{{{3x=7}}}
{{{x=7/3}}}

go to {{{y=x+1}}}..............eq.2a, substitute {{{7/3}}} for {{{x}}}

 {{{y=7/3+1}}}
{{{y=7/3+3/3}}}
{{{y=10/3}}}

go to {{{x+y+z=1}}}.......eq.1, substitute {{{7/3}}} for {{{x}}} and substitute {{{10/3}}} for {{{y}}}

{{{7/3+10/3+z=1}}}

{{{17/3+z=1}}}
{{{z=3/3-17/3}}}
{{{z=-14/3}}}

your answer is:({{{7/3}}},{{{10/3}}},{{{-14/3}}})