Question 984943
{{{2*3*2*abs(3-2x)=2*2(2x+1)}}}


{{{3*abs(3-2x)=2x+1}}}


Solve for EACH of two conditions:  3-2x is non-negative, and 3-2x is negative.


For non-negative,  {{{abs(3-2x)=3-2x}}};
For negative, {{{abs(3-2x)=-(3-2x)}}}.