Question 984953
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<pre>

   -1   *[tex \Large 7^{-1}]     *[tex \Large \frac{1}{7}]
    0   *[tex \Large 7^{0}]      *[tex \Large 1]
    1   *[tex \Large 7^{1}]      *[tex \Large 7]
    2   *[tex \Large 7^{2}]      *[tex \Large 49]
    3   *[tex \Large 7^{3}]      *[tex \Large 343]

Therefore *[tex \Large f(x)\ =\ 7^x]
</pre>
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \