Question 984484
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It is not clear whether your variable is in the denominator of a fraction or not.  That is to say, your equation could be either:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{2}x\ -\ 8\ =\ 16]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{2x}\ -\ 8\ =\ 16]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \