<PRE><B>Question 984779</B>
.
The trucks separate at a rate of 580mi/5hrs=116 mph
116 mph is the sum of the two trucks speeds.
.
S=rate of slower truck; F=rate of faster truck=S+8mph
.
S+F=116mph
S+(S+8)=116mph
2S=108mph
S=54mph ANSWER 1: The slower truck averages 54 mph.
F=S+8mph=54mph+8mph=62mph ANSWER 2: The faster truck travels 62 mph.
.
CHECK:
Distance of slower truck + distance of faster truck=580 mi
(5 hrs)(54 mph)+(5hrs)(62mph)=580 mi
270 mi+310 mi=580 mi
580 mi=580 mi</PRE>