Question 984849


the sides of the quadrilateral are {{{2x-1}}},{{{ x + 3}}}, {{{3x + 1}}}, and {{{x -1}}}
 double the length of each side:
{{{2(2x-1)}}},{{{ 2(x + 3)}}}, {{{2(3x + 1)}}}, and {{{2(x -1)}}}
{{{4x-2}}},{{{ 2x +6}}}, {{{6x + 2}}}, and {{{2x -2}}}

 then find an expression for the perimeter of the new figure:
the perimeter is equal to the sum of all sides; so, we have

{{{(4x-2)+(2x +6)+(6x + 2)+(2x -2)}}}

{{{4x-2+2x +6+6x + 2+2x -2}}}

{{{4x+2x +2x+6x +6+cross( 2)-cross(2) -2}}}

{{{14x +6 -2}}}

{{{14x +4}}}