Question 984828
{{{ 1-(4a+9b)/6a+(5a+2b)/4a= a/a-(4a+9b)/6a+(5a+2b)/4a}}}
Make each denominator equal to 12.
{{{ 1-(4a+9b)/6a+(5a+2b)/4a= (12a)/(12a)-(2(4a+9b))/(12a)+(3(5a+2b))/(12a)}}}
{{{ 1-(4a+9b)/6a+(5a+2b)/4a= (12a-2(4a+9b)+3(5a+2b))/(12a)}}}
{{{ 1-(4a+9b)/6a+(5a+2b)/4a= (12a-8a-18b+15a+6b)/(12a)}}}
{{{ 1-(4a+9b)/6a+(5a+2b)/4a= (19a-12b)/(12a)}}}