Question 984462
I'll assume a frame of reference where the 12 lb force is at 0 degrees and the 19 lb force is at 92 degrees.
{{{F[x]=12cos(0)+19cos(92)=12+19*(-.0349)=11.34}}}
{{{F[y]=12sin(0)+19sin(92)=19(0.9994)=18.99}}}
{{{F=sqrt(F[x]^2+F[y]^2)=22.1}}}
or to the nearest pound, {{{F=22}}}{{{lbs}}}