Question 984756
Use Cramer's rule,
{{{A=(matrix(3,3,
1,1,1,
1,-1,1,
2,1,-1))}}}
{{{abs(A)=6}}}
.
.
.
{{{A[x]=(matrix(3,3,
6,1,1,
2,-1,1,
1,1,-1))}}}
{{{abs(A[x])=6}}}
.
.
.
{{{A[y]=(matrix(3,3,
1,6,1,
1,2,1,
2,1,-1))}}}
{{{abs(A[y])=12}}}
.
.
.
{{{A[z]=(matrix(3,3,
1,1,6,
1,-1,2,
2,1,1))}}}
{{{abs(A[z])=18}}}
.
.
.
{{{x=abs(A[x])/abs(A)=6/6=1}}}
.
.
{{{y=abs(A[y])/abs(A)=12/6=2}}}
.
.
{{{z=abs(A[z])/abs(A)=18/6=3}}}
.
.