Question 984738
Let {{{ d }}} = number of dimes
Let {{{ q }}} = number of quarters
(1) {{{ d = 3q + 5 }}}
(2) {{{ 10d + 25q = 655 }}} ( in cents )
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(2) {{{ 2d + 5q = 131 }}}
by substitution:
(2) {{{ 2*( 3q + 5 ) + 5q = 131 }}}
(2) {{{ 6q + 10 + 5q = 131 }}}
(2) {{{ 11q = 121 }}}
(2) {{{ q = 11 }}}
and
(1) {{{ d = 3*11 + 5 }}}
(1) {{{ d = 33 + 5 }}}
(1) {{{ d = 38 }}}
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There are 38 dimes and 11 quarters
check:
(2) {{{ 10*38 + 25*11 = 655 }}}
(2) {{{ 380 + 275 = 655 }}}
(2) {{{ 655 = 655 }}}
OK