Question 984739
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Let *[tex \Large x] represent the number of half-dollars and let *[tex \Large y] represent the number of quarters.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 130]


Then *[tex \Large 50x] is the value of the half-dollars in cents and *[tex \Large 25y] is the value of the quarters in cents.  And finally, the total value of all the coins is 4000 cents. So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 50x\ +\ 25y\ =\ 4000]


Solve the 2X2 system for *[tex \Large x] and *[tex \Large y]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \