Question 984525
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The total number of 3 person committees possible given a pool of 5 potential members is given by *[tex \LARGE {{5}\choose{3}}].  The number of 3 person committees possible if Dr. Burke is excluded is *[tex \LARGE {{4}\choose{3}}].  Consequently, the probability that Burke will be on the committee is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ {{5}\choose{3}}\ -\ {{4}\choose{3}}]


Divided by


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ {{5}\choose{3}}]


Just do the arithmetic.  If the notation is unfamiliar, *[tex \LARGE {{n}\choose{k}} =\ \frac{n!}{k!(n-k)!}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \