<PRE><B>Question 984732</B>
sin(6&amp;#960;/7)cos(3&amp;#960;/28) - cos(6&amp;#960;/7)sin(3&amp;#960;/28)


sin(24&amp;#960;/28-3&amp;#960;/28) ... use the identity sin(A-B) = sin(A)cos(B) - cos(A)sin(B)


sin(21&amp;#960;/28)


sin(3&amp;#960;/4)


sqrt(2)/2 ... use the unit circle


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Final Answer: {{{sqrt(2)/2}}}
Note: the &#39;2&#39; in the denominator is NOT inside the square root</PRE>