Question 984682
Let the four consecutive integers be given by
N, N+2, N+4 and N+6

You are told that {{{N + (N+2) + 2*((N+4)+(N+6)) = 742}}}
Solve for N
{{{N + N + 2 + 2N+8 +2N+12 = 742}}}
{{{6N + 22 = 742}}}
{{{6N = 720}}}
{{{N = 120}}}
So the numbers are 120, 122, 124, and 126

Check your answer. is {{{742 = 120+122 + 2(124+126)}}}