Question 984681
Let the third number be given by N
You are told a  number is 60% more than N, so that is 1.6N
You are told a second number is 20% more than N, so that is 1.2N

You are asked to find how much more,percentage-wise, the first number is with respect to the second number.

{{{((Firstnumber)/(secondNumber)) * 100  }}} yields that result.
Plug in and get
{{{((1.6N)/(1.2N)) * 100}}} %
{{{(1.6/1.2) * 100}}}%
{{{1.333 * 100}}} %
{{{133.33}}} %

So the first number is 33.33% larger than the second one