Question 984514
try to simplify each and get rid of the denominators
3(x+{{{6/5}}})+{{{y/2}}} + 2z = 25
distribute
3x+{{{18/5}}}+{{{y/2}}} + 2z = 25
Multiply equation by 10, cancel the denominators
10(3x) + 2(18) + 5y + 10(2z) = 10(25)
30x + 36 + 5y + 20z = 250
30x + 5y + 20z = 250 - 36
30x + 5y + 20z = 214
:
{{{x/2}}}+5y-{{{2/4}}}+z=17
reduce fraction
{{{x/2}}}+5y-{{{1/2}}}+z=17
multiply by 2
x + 2(5y) - 1 + 2z = 2(17)
x + 10y + 2z = 34 + 1
x + 10y + 2z = 35
:
x-(2(y-{{{1/7}}}) - 3z = -22
Distribute
x-(2y - {{{2/7}}}) - 3z = -22
minus a minus is a plus
x - 2y + {{{2/7}}} - 3z = -22
multiply equation by 7
7x - 7(2y) + 2 -  7(3z) = 7(-22)
7x - 14y - 21z = -154 - 2
7x - 14y - 21z = -156
:
This is how you simplify the equations, but I checked the solutions using the matrix feature on my Ti83 and none of the solutions are integers, either I made a mistake here or something is wrong with the problem.  CK  ankor@att.net