Question 984489
I'm assuming you mean the force parallel to the road and not the force normal to the road.
{{{F[p]=W*sin(theta)}}}
{{{theta=4+20/60=4&1/3}}}

{{{F[p]=17900*.01740252}}}
{{{F[p]=311.5}}}
Nearest ten pounds would make it,
{{{F[p]=310}}}{{{lbs}}}