Question 984499


<pre>
Instead of doing your problem for you, I'll do another one that is just
exactly in every detail and step like yours.  Sop you can use it as a
model to go by.  I'll do this one instead:
</pre>
a|x + b| + c = 0
To 2 decimal places, what is the value of the greater of the two solutions when a = 12, b = 10 and c = -8?
<pre>
12|x + 10| + (-8) = 0

12|x + 10| = 8

Divide both sides by 4

3|x + 10| = 2

Since what's inside the absolute value can be either positive
or negative, we make two equations, one where x + 10 is positive
and one where x + 10 is negative.

3[+(x + 10)] = 2     or     3[-(x + 10)] = 2

3x + 30 = 2         or          -3x - 30 = 2
     3x = -28       or               -3x = 32
      x = {{{-28/3}}}     or      x = {{{-32/3}}}
      x = -9.33                   x = -10.67

The greater of those two solutions, since they are both negative,
is the one that's the least far below zero, and -9.23 is not
as far below zero as -10.67.

So the answer is -9.33

Now do your problem exactly the same way, step by step.

Edwin</pre>