Question 984487
x/y=2/3
(x+2)/(y+2)=3/4
cross-multiply both
3x=2y; 3x-2y=0
4x+8=3y+6
4x-3y=-2
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Multiply the first equation by 4 and the second equation by (-3) and add it to the first
12-8y=0
-12x+9y= 6
y=6
x=4
(x+2)=6
(y+2)=8; 6/8=3/4
;
3n-2d=0
4n-3d=0, rearranging
multiply top by 3 and bottom by (-2)
9n-6d=0
-8n+6d=0
n=0
d=0
Indeed, that is the only way that 4n+2=3d+2
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3n=2d; 4n-3d=-2, rearranging. Do it by substitution
n=(2/3)d; 4n=(8/3)d
(8/3)d-(9/3)d=-2
(-1/3)d=-2
d=6, multiplying both sides by (-3)
n=4 substituting d into the first and solving for 3n
4(4)+8=3(6)+6
24=24 check
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