Question 984450
Since they both equal y, set them equal to each other.
{{{x^2+3=x+5}}}
{{{x^2-x-2=0}}}
{{{(x-2)(x+1)=0}}}
Two solutions:
{{{x-2=0}}}
{{{x=2}}}
and
{{{x+1=0}}}
{{{x=-1}}}
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Now go back with each x and find the corresponding y value.
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You can verify by plugging the values in the equation or by graphing.
Here's a graph.
*[illustration fd13.JPG].