Question 984406
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{x}{\sqrt{x\ -\ 1}}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{d^2x}{dy^2}\ =\ -\frac{x\ -\ 4}{4(x\ -\ 1)^{\frac{5}{2}}}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{d^3x}{dy^4}\ =\ \frac{3(x\ -\ 6)}{8(x\ -\ 1)^{\frac{7}{2}}}]


If you need the steps, that is a lot of work.  Write back and we can discuss my fee.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \