Question 984409
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I already did this one for you, Question 984344.  But here it is again.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ \frac{5}{x}]


Re-write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ 5x^{-1}]


Then use the power rule


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\text{d}y}{\text{d}x}\ =\ -5x^{-2}\ =\ -\frac{5}{x^2}]


You can evaluate *[tex \Large f'(-1)] yourself.


As for the other one, here is the graph. You should be able to figure out the rest.


*[illustration limitquestion].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \