Question 84055
Write equation for the line . Use slope intercept form if it its possible. 
# 1
through (-1,4) perpendicular to 9x+5y=11 
this is what i have done so far am i correct 
9x+5y=11
5y=-9x+11
y=-(9)/(5)+(11)/(5) 
so then i use the reciprocal slope <b><font face = "courier new" color = "red"> with the opposite sign</font></b> 
which will be (5)/(9) and use the point that they gave me. so now i do the following: 
y = mx+b
4 = (5)/(9) * (-1) +b
(41)/(9)=b 
y= (5)/(9)x+(41)/(9) 
<pre><font color = "red"><b>
That one is correct!
</font></pre> 
#2
through (3,-5),parallel to y =4 
for this one i have no idea?
<pre><font color = "red"><b>
y = 4 is this horizontal line

{{{graph(300,300, -4, 10, -7, 7, 4)}}} 

now plot the point (3,-5)

{{{drawing(300,300, -4, 10, -7, 7, 

locate(2.8,-4.6, "o<--the_point_(3,-5)"),
graph(300,300, -4, 10, -7, 7, 4) ) }}} 
 
Now draw a green line parallel to
the given line through that point.
It will also be horizontal:

{{{drawing(300,300, -4, 10, -7, 7, 

locate(2.8,-4.6, o),
graph(300,300, -4, 10, -7, 7, 4, -5),

locate(1.8,-3.6,"(3,-5)")
 ) }}}

The equation of any horizontal line is y = b,
where b is the y-coordinate of any and every 
point on the line.  So since (3,-5) is on the 
line and it has y-coordinate -5, the equation
of the green line is y = -5.

Edwin</pre>