Question 984385
Using the equation {{{2d=(at^2)}}}

a.solve for a
{{{d=(at^2)/2}}}
{{{2d=(at^2)}}}
{{{2d(t^2)=a}}}
====================
b.solve for t
{{{2d=(at^2)}}}
{{{t^2 = 2d/a}}}
{{{t = sqrt(2d/a)}}}
------------------------
c.solve for 2
2 = 2