Question 984376
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The angle of vector *[tex \Large \vec{x}\ =\ a\hat{i}\ +\ b\hat{j}] is given by *[tex \Large \varphi\ =\ \tan^{-1}\left(\frac{b}{a}\right)]


If the angle of vector *[tex \Large \vec{u}] is *[tex \Large \theta] and the angle of vector *[tex \Large \vec{v}] is *[tex \Large \phi], then the angle between *[tex \Large \vec{u}] and *[tex \Large \vec{v}] is *[tex \Large |\theta\ -\ \phi|]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \