Question 984357
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ v_f^2\ =\ v_i^2\ +\ 2ad]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ v_i^2\ =\ v_f^2\ -\ 2ad]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ v_i\ =\ \pm\sqrt{v_f^2\ -\ 2ad}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \