Question 984335

{{{z^2-4z+4}}} ...I guess you need to factor it; if yes, then

{{{z^2-2z-2z+4}}} 

{{{(z^2-2z)-(2z-4)}}}

{{{z(z-2)-2(z-2)}}}

{{{(z-2)(z-2)}}}

but, if you need to solve for {{{z}}}, then you will have to meke it equal to zero first

{{{(z-2)(z-2)=0}}}

if {{{(z-2)=0}}}=> {{{z=2}}} (one double solution)