Question 84068
0,<pre>
The measure of a big-screen television is given by the length of a diagonal
across the screen. A 33-inch television has a width of 26.4in. Find the height
of the screen to the nearest tenth of an inch.

{{{drawing(400,266.67,0,30,0,20, triangle(0,0,0,19.8,26.4,19.8),
   triangle(0,0,26.4,0,26.4,19.8), locate(9,2,"a=width=24.4 in"),
   locate(9,10,"c=diagonal=33 in"),locate(25,12,"b=height=?") 

 )}}}
<b>
Just use the Pythagorean theorm:

           c² = a² + b²
          33² = 24.4² + b²
         1089 = 696.96 + b²
1089 - 696.96 = b²
       392.04 = b²
{{{sqrt(392.04)}}} = b
  b = 19.8 inches

Edwin</pre>