<PRE><B>Question 984266</B>
In y = mx+b, the b is always the y-intercept. So b = -2



y = mx+b


y = mx+(-2)


y = mx - 2



Now plug in the point (4,0) from the fact that the x intercept is 4.


y = mx - 2


0 = m(4) - 2


0 = 4m - 2


2 = 4m


4m = 2


m = 2/4


m = 1/2 ... take note that the slope is positive, not negative


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In the end, the equation in slope intercept form is {{{y = expr(1/2)x - 2}}}


In point slope form, the equation is {{{y - 0 = expr(1/2)(x-4)}}}. You can use the other point to get {{{y + 2 = expr(1/2)(x-0)}}}


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