Question 984136
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Use the fact that the sum of the measures of the three angles of a triangle is 180 degrees to find the third angle.  Then use the Law of Sines to calculate the two missing sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{a}{sinA}\ =\ \frac{b}{sinB}\ =\ \frac{c}{sinC}] 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \