Question 984208
x^3+x^2-4x=0 to find roots
factor out x
x(x^2+x-4)=0
x=0 is one root
x=(1/2)(-1+/- sqrt (1+16))  That works ;;;; sqrt 17=4.12
x=1.56, -2.56

y intercept =0,0
{{{graph(300,200,-5,5,-10,10,x^3+x62-4x)}}}