Question 984210
to find an inverse of {{{f(x)=2x+7}}}, first recall that  {{{f(x)=y}}}


{{{y=2x+7}}} now swap {{{x}}} and {{{y}}}

{{{x=2y+7}}}....solve for {{{y}}}

{{{x-7=2y}}}

{{{(x-7)/2=y}}}

so, inverse is:

{{{f^-1(x)=(x-7)/2}}}


{{{ graph( 600, 600, -10, 10, -10, 10 ,2x+7, (x-7)/2) }}}