Question 83967
Question:


Rewrite the middle term as the sum of two terms and then factor by grouping.
     x^2 – 2x – 63


Answer:


Here find out two numbers, whose sum is -2{that is coefficient of 'x' term and whose product is -63(that is constant term)


Such two numbers are  -9 and +7

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Now rewrite the given expression as follows...


x^2 - 9x + 7x - 63 = 0



Now group the terms...





(x^2 - 9x) + (7x - 63) = 0




Now take take out the common term from both the groups...




==> x( x-9) + 7(x-9) = 0



Now (x-9) is common in both the terms...




==> (x-9) (x-7)




So the factors of given expression are (x-9) and (x-7).




Hope you found the explanation useful....




Regards...




Praseena.