Question 984118
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A conditional is false whenever the antecedent is true and the consequent is nevertheless false.  P, the antecedent, is true, but since Q is false, Q and R is false, the consequent is false and therefore the conditional is false.


The entire truth table for your statement is:
<pre>
  P   Q   R   Q&R   P->(Q&R)
  T   T   T    T       T
  T   T   F    F       F
* T   F   T    F       F
  T   F   F    F       F
  F   T   T    T       T
  F   T   F    F       T
  F   F   T    F       T
  F   F   F    F       T
</pre>

The line with the asterisk is the given situation.

John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \