Question 983912
{{{(2x^2y)(5x^(-2)y^3)}}}



{{{(2*5)*(x^2*x^(-2))*(y*y^3)}}} Rearrange terms



{{{10*x^(2+(-2))*y^(1+3)}}} Use the rule {{{x^a*x^b = x^(a+b)}}}



{{{10*x^(0)*y^(4)}}}



{{{10*1*y^(4)}}} Use the rule {{{x^0=1}}} (x is any number but 0)



{{{10y^(4)}}}



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So {{{(2x^2y)(5x^(-2)y^3)}}} simplifies to {{{10y^(4)}}}