Question 983892
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If one of the acute angles of a right triangle measures *[tex \Large \frac{\pi}{4}] radians, then the right triangle is isosceles.  Hence, the sides are in ratio:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 1\,:\,\frac{sqrt{2}}{2}\,:\,\frac{sqrt{2}}{2}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \