Question 983886
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If *[tex \Large \cos(t)\ =\ 1] then *[tex \Large \sin(t)\ =\ 0].  Then *[tex \Large \csc] is the reciprocal of *[tex \Large \sin] and *[tex \Large \cot] has *[tex \Large \sin] in the denominator.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \