Question 983864

{{{7}}},{{{16}}},{{{8}}},{{{27}}},

starting from {{{7}}} every other digit is adding one to the term {{{2}}} before it in the sequence; so we have {{{10}}} as the {{{7th}}} term

we need to find the {{{6th}}} term.
 
we also have {{{16/8 = 2}}}, {{{27/9=3}}}

so we need {{{x/10=4}}} solve for {{{x}}}=>{{{ x = 40}}}
 
thus the list is  {{{7}}}, {{{16}}}, {{{8}}}, {{{27}}}, {{{9}}}, {{{40}}}, {{{10}}}