Question 983842
given:

C ({{{-1}}}, {{{2}}}), 
D ({{{-2}}}, {{{-1}}}), 
E ({{{2}}}, {{{-2}}}), and 
F ({{{1}}}, {{{1}}})

use the distance formula, then add all of the distances 

 the distance between points
C ({{{-1}}}, {{{2}}}) and  D ({{{-2}}}, {{{-1}}}) is {{{CD}}}


*[invoke Distance_Formula_for_Coordinate_Plane -1, 2, -2, -1] 




the distance between points
 E ({{{2}}}, {{{-2}}}), and F ({{{1}}}, {{{1}}})is {{{EF}}}

*[invoke Distance_Formula_for_Coordinate_Plane 2, -2, 1, 1]



the distance between points

C ({{{-1}}}, {{{2}}}) and E ({{{2}}}, {{{-2}}}) is {{{CE}}}

*[invoke Distance_Formula_for_Coordinate_Plane -1, 2, 2, -2]


the distance between points

D ({{{-2}}}, {{{-1}}}) and F ({{{1}}}, {{{1}}}) is {{{DF}}}


*[invoke Distance_Formula_for_Coordinate_Plane -2, 11, 1, 1]



so,

{{{CD= 3.16}}} units
{{{EF=3.16}}}
{{{CE=5}}}
{{{DF=10.44}}}

then, {{{P=3.16+3.16+5+10.44=21.76}}}