Question 983773
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If 12 men can do a job in 10 days, then 12 men can do *[tex \Large \frac{1}{10}] of the job in 1 day, and then 1 man can do *[tex \Large \frac{1}{120}] of the job in 1 day.  Similarly, 1 woman can do *[tex \Large \frac{1}{240}] of the job in 1 day.


So 8 men and 4 women working for 9 days do *[tex \Large \frac{8\,\times\,9}{120}\ +\ \frac{4\,\times\,9}{240}\ =\ \frac{90}{120}] of the job, leaving *[tex \Large \frac{30}{120}] of the job for 8 men and 14 women to accomplish in *[tex \Large x] days, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{8x}{120}\ +\ \frac{14x}{240}\ =\ \frac{30}{120}]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \