Question 983616
See "ANOTHER IDEA", below.


Point-Slope Equation Form might be easiest to use.


{{{y-y=m(x-(-3))}}}
{{{0=((2-y)/(x+3))(x+3)}}}
{{{0=2-y}}}
{{{y=2}}}?


Try slope-intercept form instead.
{{{m=(2-y)/(x+3)}}}
y=mx+b
b=y-mx
{{{b=y-((2-y)/(x+3))(-3)}}}
-
{{{y=((2-y)/(x+3))x+(y-((2-y)/(x+3))(-3))}}}
This will not be a line;  NOT be a line!!


What you do with the two given points depends on what kind of equation and graph shape you expect, and maybe more than just those two ordered pairs.



<b>Another idea:</b>
Each of your given points represents a line ---- EACH of the given points.
(-3,y)  is the line  x=-3.  All real values for y are included.
(x,2)  is the line  y=2.  All real values for x are included.
These are two separate lines.