Question 983522
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The sides of an isosceles right triangle are in proportion *[tex \Large 1:\frac{\sqrt{2}}{2}:\frac{\sqrt{2}}{2}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \