Question 983420
Y-intercept : Set {{{x=0}}} and solve for {{{y}}}.
{{{y=0^2-4(0)+3}}}
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X-intercept : Set {{{y=0}}} and solve for {{{x}}}.
{{{0=x^2-4x+3}}}
Add half of the {{{(-4)}}} term squared to both sides. 
{{{4=x^2-4x+4+3}}}
{{{4=(x-2)^2+3}}}
{{{(x-2)^2=1}}}
{{{x-2=0 +- 1}}}
Now add 2 to both sides to get the x-intercepts.