Question 983343
Rational Roots Theorem; synthetic division trying roots -1,-2,-5,1,2,5; maybe +10 or -10.


<pre>

-1   |   1   -3   6   10
     |       -1   4   -10
     _____________________
         1   -4   10   0 -------- {{{highlight(-1)}}} is a (real) root.

Now use quadratic equation skills to get the two other roots.

</pre>


{{{x^2-4x+10=0}}}-----comes from the quotient of the previous synthetic division.


{{{x=(4+- sqrt(16-4*10))/2}}}


{{{x=(4+- sqrt(4(4-10)))/2}}}


{{{x=(4+- 2sqrt(-6))/2}}}


{{{x=2+- sqrt(-6)}}}


{{{highlight(x=2+- i*sqrt(6))}}}-----these are the two complex roots.


FINISHED.
Degree of equation is three; so only three roots.