Question 983244
{{{y=x^2-14x+49}}}.......write it in vertex form {{{y=(x-h)^2+k}}} where {{{h}}} and {{{k}}} are {{{x}}} and {{{y}}} coordinates of vertex

{{{y=(x^2-14x+_)-_+49}}}


{{{y=(x^2-14x+7^2)-7^2+49}}}

{{{y=(x-7)^2-49+49}}}

{{{y=(x-7)^2}}}

as you can see, {{{h=7}}} and {{{k=0}}}, so vertex is at ({{{7}}},{{{0}}})


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(7,0,.12),locate(7,-0.4,V(7,0)),
 graph( 600, 600, -10, 10, -10, 10, (x-7)^2)) }}}