Question 80043
{{{7^(6x-5)=7^(2(4x+10))}}}
{{{7^(6x-5)=7^(8x+20)}}}
TAKE LOG FOR BOTH SIDES
{{{ (6x-5)Log7=(8x+20)Log7}}}
CANCEL OUT THE LOG7
ull be left with 
6x-5=8x+20
now solve normally and ull get 
-25=2x
so x=-12.5