Question 982081
<pre>
Look at this:

{{{drawing(200,200,-1.1,1.1,-1.1,1.1,

triangle(-1,-1,0,-1,-1,0),
triangle(1,-1,0,-1,1,0),
triangle(0,-1,0,0,-1,0),
triangle(0,-1,0,0,1,0),
triangle(-1,0,0,1,0,0),
triangle(0,1,0,0,1,0),
triangle(-1,1,0,1,-1,0),
triangle(1,1,0,1,1,0) )}}}

8 congruent isosceles right triangles make up the big outer
square, and only 4 of them make up the inner (diamond-shape)
square, joining the midpoints of the consecutive
sides of the outer square.

That means each square will have 1/2 as much area as the preceding square.

The area of the first square is 8<sup>2</sup>=64 and the next square will
have half that area or 32.

Now you can do the problem.  It will be 64 + 32 + ? + ? + ? + ? = ?

Edwin</pre>