Question 983142
n, an integer


Two consecutive odd numbers,  2n+1, 2n+3


The description,  {{{highlight((2n+1)^2+(2n+3)^2=130)}}}


Beginning of steps to solve
{{{4n^2+4n+1+4n^2+12n+9-130=0}}}
{{{8n^2+16n+10-130=0}}}
{{{8n^2+16n-120=0}}}
{{{n^2+2n-15=0}}}



{{{n=3}}} so use this to evaluate the two numbers.