Question 983141
{{{(4x+12)^2 = 50}}}
{{{4x + 12 = 0 +- sqrt(50)}}}
{{{4x + 12 = 0 +- 5sqrt(2)}}}
{{{4x = -12 +- 5sqrt(2)}}}
{{{x = (-12 +- 5sqrt(2))/4}}}


so {{{x = (-12 + 5sqrt(2))/4}}},{{{(-12 - 5sqrt(2))/4}}}